## Finding average value from a double integral

Find the average value of f over the given rectangle. f(x, y) = e^y \sqrt{x + e^y} , R = [0, 4] \times [0, 1]Watch the full video at:https://www.numerade.com

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## Answer to Question #139339 in Calculus for Promise Omiponle

Average value of f = 1 A ∫ ∫ R f (x, y) d A Where A is the area of the region R We can say: R = [− 1, 1] × [0, 5] Therefore A = 2 ⋅ 5 = 10 Average value of f = 1 10 ∫ − 1 1 [∫ 0 5 x 2 y d y] d x Integrate with

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## Find the average value of f(x, y) = (5e^y) sqrt(x + e

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## How to find the average value of $f(x,y)$ on \$R=\{(x,y)

The average value of f(x, y) in the given rectangle is 25. So we want to find the average value of f(x, y) = 3*x^2*y on the rectangle with vertices (−5, 0), (−5, 3), (5, 3), (5, 0).
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