Find the exact value of cos(arcsin(one fourth)). For full credit, explain your reasoning.----You want the cosine of the angle whose sine is 1/4. Since the sin(t) is 1/4, y = 1 and r = 4 Then x =

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Find the Exact Value cos (arcsin (5/13)) cos (arcsin( 5 13)) cos ( arcsin ( 5 13)) Draw a triangle in the plane with vertices ⎛⎝√12 − ( 5 13)2, 5 13⎞⎠ ( 1 2 - ( 5 13) 2, 5 13), ⎛⎝√12 −( 5 13)2,0⎞⎠ (

Therefore, cos(arcsin(−3 5)) cos ( arcsin ( - 3 5)) is √12 −(−3 5)2 1 1 2 - ( - 3 5) 2 1. Divide √12 −(−3 5)2 1 2 - ( - 3 5) 2 by 1 1. One to any power is one. Use the power rule (ab)n = anbn ( a b) n

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Find the exact value of cos (arcsin (five divided by thirteen

cos (arcsin( 3 5) + arccos ( 5 13)) cos ( arcsin ( 3 5) + arccos ( 5 13)) Simplify each term. Tap for more steps cos(0.6435011+ 1.1760052) cos ( 0.6435011 + 1.1760052) Add 0.6435011

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Give the exact value of the expression. cos (arcsin 5/13 + arccos 3/5)