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(3) to find the length of the path over the given interval. (1 + 2t, 2 + 4t), 1 ≤ t ≤ 4. A: Given x, y=1+2t, 2+4t where dxdt=2, dydt=4 a 1≤t≤4.

Solve NowCalculate the length of the path over the given interval: c(t) = (3t^2, 4t^3), 2 . Math. Calculate the length of the path over the given interval: (sin6t, cos6t), 0 . Math. A rectangular flower bed has

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(6 sin 3t, 6 cos 3t), 0 lessthanorequalto t lessthanorequalto pi Use the Arc Length Theorem to calculate the length S of the given path over the given interval. (sin theta- theta cos theta, cos theta + theta sin theta), 0 < theta < 12 S =

arc\:length\:x,\:0,\:1; arc\:length\:\sqrt{1-x^{2}} arc\:length\:\ln(\sec(x)),\:[0,\:\frac{\pi}{4}] arc\:length\:y=2x^{2}+3,\:0\le x\le 1

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Solution for Find the length of the path over the given interval. (sin 3t, cos 3t), 0 ≤ t ≤ π

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Q: Find the length of the path over the given interval. (sin 3t, cos 3t), 0 ≤ t ≤ π. A: xt, yt=sin3t, cos3t, 0≤t≤π Here, xt=sin3t, yt=cos3t Now differentiating with respect to t, we get