We first look for the general solution of the PDE before applying the initial conditions. Combining the characteristic and compatibility equations, dxds = y + u, (2.11) dyds = y, (2.12) duds = x − y (2.13) we seek two independent first integrals. Equations (2.11) and (2.13) give d(x + u)ds= x + u, and equation (2.12) 1y dyds = 1. Now See more
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3 General solutions to first-order linear partial differential equations can often
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